180=((-j-2j)^2)+((-7+5)^2)

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Solution for 180=((-j-2j)^2)+((-7+5)^2) equation: 



180=((-j-2j)^2)+((-7+5)^2)

We move all terms to the left:

180-(((-j-2j)^2)+((-7+5)^2))=0

We add all the numbers together, and all the variables

-(((-3j)^2)+((-2)^2))+180=0



We calculate terms in parentheses: -(((-3j)^2)+((-2)^2)), so:

((-3j)^2)+((-2)^2)

We add all the numbers together, and all the variables

((-3j)^2)+4



We calculate terms in parentheses: +((-3j)^2), so:

(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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(-3j)^2





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